How can module determine its own path?

[Robert Kern]

On 2009-10-30 18:40 PM, Stef Mientki wrote:
> Robert Kern wrote:
>> On 2009-10-30 12:19 PM, kj wrote:
>>> How can a module determine the path of the file that defines it?
>>> (Note that this is, in the general case, different from sys.argv[0].)
>>
>> __file__
>>
> but for modules launched with execfile, __file__ doesn't exists.

Modules launched from execfile() using a properly initialized namespace dict do.

-- 
Robert Kern

"I have come to believe that the whole world is an enigma, a harmless enigma
  that is made terrible by our own mad attempt to interpret it as though it had
  an underlying truth."
   -- Umberto Eco