lambda forms within a loop
Lawrence D'Oliveiro
ldo at geek-central.gen.new_zealand
Sun Oct 25 00:34:11 EDT 2009
In message <mailman.1990.1256441598.2807.python-list at python.org>, Michal
Ostrowski wrote:
> def MakeLambdaBad():
> a = []
> for x in [1,2]:
> a.append(lambda q: x + q)
> return a
Here's another form that should work:
def MakeLambdaGood2() :
a = []
for x in [1, 2] :
a.append((lambda x : lambda q : x + q)(x))
return a
It's all a question of scope.
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