Separate namespace from file hierarchy?

[Peng Yu]

Suppose I have the dirname/both.py, which has the definitions of
classes A and B. I can use this module in the following code.

#################
import dirname.both

a=dirname.both.A()
b=dirname.both.B()
####################

When the definitions of A and B become too long, it is better that I
put them in two different files (to improve the maintainability), for
example, dirname/A.py and dirname/B.py. Now, the code becomes

#################
import dirname.A
import dirname.B

a=dirname.A.A() #two A seems redundant
b=dirname.B.B() #two B seems redundant
####################

However, the last two lines are annoying to me, as 'A' and 'B' appears
twice, which seems redundant.

In C++, I can define namespace independent of file hierarchy (as shown
in the following code). I'm wondering if there is a way to make the
namespace separate from the file hierarchy in python.

#include <dirname/A.hpp>
#include <dirname/B.hpp>

int main() {
   dirname::A a = dirname::A()
   dirname::B b = dirname::B()
}