Logging exceptions to a file

[segfaulthunter]

On May 7, 1:19 pm, Pierre GM <pierregmc... at gmail.com> wrote:
> On May 7, 5:32 am, Lie Ryan <lie.1... at gmail.com> wrote:
>
>
>
> > Pierre GM wrote:
> > > All,
> > > I need to log messages to both the console and a given file. I use the
> > > following code (on Python 2.5)
>
> > >>>> import logging
> > >>>> #
> > >>>> logging.basicConfig(level=logging.DEBUG,)
> > >>>> logfile = logging.FileHandler('log.log')
> > >>>> logfile.setLevel(level=logging.INFO)
> > >>>> logging.getLogger('').addHandler(logfile)
> > >>>> #
> > >>>> mylogger = logging.getLogger('mylogger')
> > >>>> #
> > >>>> mylogger.info("an info message")
>
> > > So far so good, but I'd like to record (possibly unhandled) exceptions
> > > in the logfile.
> > > * Do I need to explicitly trap every single exception ?
> > > * In that case, won't I get 2 log messages on the console (as
> > > illustrated in the code below:
> > >>>> try:
> > >>>>     1/0
> > >>>> except ZeroDivisionError:
> > >>>>     mylogger.exception(":(")
> > >>>>     raise
>
> > > Any comments/idea welcomed
> > > Cheers.
>
> > Although it is usually not recommended to use a catch-all except, this
> > is the case where it might be useful. JUST DON'T FORGET TO RE-RAISE THE
> > EXCEPTION.
>
> > if __name__ == '__main__':
> >      try:
> >          main():
> >      except Exception, e:
> >          # log('Unhandled Exception', e)
> >          raise
>
> OK for a simple script, but the (unhandled) exceptions need to be
> caught at the module level. Any idea?

Override sys.excepthook. http://docs.python.org/library/sys.html#sys.excepthook