Mark Dickinson <dickinsm at gmail.com> writes: > It looks as though you're treating (a portion of?) the Koch curve as > the graph of a function f from R -> R and claiming that f is > uniformly continuous. But the Koch curve isn't such a graph (it > fails the 'vertical line test', I think you treat it as a function f: R -> R**2 with the usual distance metric on R**2.