Simple CGI-XMLRPC failure

[Jeff McNeil]

I don't have the version in front of me now as that was on my home
machine, but Python was the same right down to the revision number.
Unless you've mucked with it, it's the same file that I've got on my
box.

Jeff

On Jan 13, 10:51 am, "Mike MacHenry" <dski... at ccs.neu.edu> wrote:
> I figured it was some kind of bug. Must be either a bug with my
> version of either the library (most likely) or perhaps some weird
> environment setting that I have set incorrectly (also likely). How can
> I figure out which version of SimpleXMLRPCServer I'm running? Do you
> run Ubuntu by any chance? If you which version?
>
> Does anyone know of any environment settings I could look into on
> Apache or Python?
>
> -mike
>
> On Mon, Jan 12, 2009 at 9:02 PM, Jeff McNeil <j... at jmcneil.net> wrote:
> > On Jan 12, 12:40 pm, "Mike MacHenry" <dski... at ccs.neu.edu> wrote:
> >> I am having a difficult time understanding why my very simple
> >> CGI-XMLRPC test isn't working. I created a server to export two
> >> functions, the built-in function "pow" and my own identity function
> >> "i". I run a script to call both of them and the "pow" work fine but
> >> the "i" gives me an error that says my XMLRPC server doesn't support
> >> than name. Here is the code for both files and the output:
>
> >> #!/usr/bin/env python
> >> #This file is /usr/lib/cgi-bin/roundwarerpc.py
> >> from SimpleXMLRPCServer import CGIXMLRPCRequestHandler
> >> def i(x):
> >>         return x
> >> server = CGIXMLRPCRequestHandler()
> >> server.register_function(pow)
> >> server.register_function(i)
> >> server.handle_request()
>
> >> #!/usr/bin/env python
> >> #This file is ~/test.py
> >> import xmlrpclib
> >> server = xmlrpclib.ServerProxy("http://localhost/cgi-bin/roundwarerpc.py")
> >> print server.pow(2,3)
> >> print server.i(10)
>
> >> #This is the STDOUT and STDERR when running ~/test.py
> >> dskippy at dskippy-laptop:$ python test.py 8
> >> Traceback (most recent call last):
> >>   File "test.py", line 4, in <module>
> >>     print server.test(10)
> >>   File "/usr/lib/python2.5/xmlrpclib.py", line 1147, in __call__
> >>     return self.__send(self.__name, args)
> >>   File "/usr/lib/python2.5/xmlrpclib.py", line 1437, in __request
> >>     verbose=self.__verbose
> >>   File "/usr/lib/python2.5/xmlrpclib.py", line 1201, in request
> >>     return self._parse_response(h.getfile(), sock)
> >>   File "/usr/lib/python2.5/xmlrpclib.py", line 1340, in _parse_response
> >>     return u.close()
> >>   File "/usr/lib/python2.5/xmlrpclib.py", line 787, in close
> >>     raise Fault(**self._stack[0])
> >> xmlrpclib.Fault: <Fault 1: '<type \'exceptions.Exception\'>:method "i"
> >> is not supported'>
>
> >> Does anyone know what might be wrong with this?
>
> >> Thanks for the help,
> >> -mike
>
> >> p.s.
> >> Python 2.5.2 (r252:60911, Jul 31 2008, 17:28:52)
> >> [GCC 4.2.3 (Ubuntu 4.2.3-2ubuntu7)] on linux2
> >> Server version Apache/2.2.8 (Ubuntu)
> >> Server built: Jun 25 2008 13:54:13
>
> > I copied your code verbatim and I don't have any issues with it at
> > all. Same version of Python, same version of Apache.
>
> > In SimpleXMLRPCServer.py, register_function adds directly to a
> > self.funcs dictionary, so an instance variable of the same name
> > shouldn't hurt anything.  That exception is only raised when a
> > self.funcs lookup raises a KeyError unless you're registering an
> > instance.
>
> > --
> >http://mail.python.org/mailman/listinfo/python-list