Is there a better algorithm?

[Andreas Waldenburger]

On Fri, 02 Jan 2009 19:55:43 +0100 Markus Brueckner <news at slash-me.net>
wrote:

> g = ( ((e[0],None,e[1]) if len(e)==2 else (e[0],e[1],e[2])) for e in
> L)

If this isn't proof of Python's versatility, I don't know what is. In
one line it can mimic both Lisp and Perl. Sweet.

:)
/W

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