Pythonic way to determine if one char of many in a string

[Chris Rebert]

On Sun, Feb 15, 2009 at 9:17 PM,  <python at bdurham.com> wrote:
> I need to test strings to determine if one of a list of chars is in the
> string. A simple example would be to test strings to determine if they have
> a vowel (aeiouAEIOU) present.
>
> I was hopeful that there was a built-in method that operated similar to
> startswith where I could pass a tuple of chars to be tested, but I could not
> find such a method.
>
> Which of the following techniques is most Pythonic or are there better ways
> to perform this type of match?
>
> # long and hard coded but short circuits as soon as match found
> if 'a' in word or 'e' in word or 'i' in word or 'u' in word or ... :
>
> -OR-
>
> # flexible, but no short circuit on first match
> if [ char for char in word if char in 'aeiouAEIOU' ]:

Just use the fairly new builtin function any() to make it short-circuit:

if any(char.lower() in 'aeiou' for char in word):
    do_whatever()

Cheers,
Chris

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