Pythonic way to determine if one char of many in a string

[python at bdurham.com]

Nicolas,

> I would go for something like:
> 
> for char in word:
>     if char in 'aeiouAEIUO':
>         char_found = True
>         break
> else:
>     char_found = False
>
> It is clear (imo), and it is seems to be the intended idiom for a 
> search loop, that short-circuits as soon as a match is found.

Thank you - that looks much better that my overly complicated attempts.

Are there any reasons why I couldn't simplify your approach as follows?

for char in word:
    if char in 'aeiouAEIUO':
        return True
return False

Cheers,
Malcolm