Breaking Python list into set-length list of lists

Mensanator mensanator at aol.com
Thu Feb 12 00:41:30 EST 2009


On Feb 11, 10:58�pm, Jason <elgrandchig... at gmail.com> wrote:
> Hey everyone--
>
> I'm pretty new to Python, & I need to do something that's incredibly
> simple, but combing my Python Cookbook & googling hasn't helped me out
> too much yet, and my brain is very, very tired & flaccid @ the
> moment....
>
> I have a list of objects, simply called "list". �I need to break it
> into an array (list of lists) wherein each sublist is the length of
> the variable "items_per_page". �So array[0] would go from array[0][0]
> to array[0][items_per_page], then bump up to array[1][0] - array[1]
> [items_per_page], until all the items in the original list were
> accounted for.
>
> What would be the simplest way to do this in Python? �And yes, I
> realize I should probably be taking Programming 101.....

>>> items_per_page = 20
>>> x = range(113)
>>> layout = divmod(113,20)
>>> if layout[1]>0:
	pages = layout[0]+1
else:
	pages = layout[0]
>>> array = [ x[i*items_per_page:i*items_per_page+items_per_page]  for i in xrange(pages)]
>>> array
[[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18,
19], [20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35,
36, 37, 38, 39], [40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52,
53, 54, 55, 56, 57, 58, 59], [60, 61, 62, 63, 64, 65, 66, 67, 68, 69,
70, 71, 72, 73, 74, 75, 76, 77, 78, 79], [80, 81, 82, 83, 84, 85, 86,
87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99], [100, 101, 102,
103, 104, 105, 106, 107, 108, 109, 110, 111, 112]]



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