Sort the values of a dict

[David Robinow]

On Fri, Dec 18, 2009 at 5:34 PM, mattia <gervaz at gmail.com> wrote:
> Hi all, I have a dictionary that uses dates and a tuples ad key, value
> pairs. I need to sort the values of the dict and insert everything in a
> tuple. The additional problem is that I need to sort the values looking
> at the i-th element of the list. I'm not that good at python (v3.1), but
> this is my solution:
>
>>>> d = {1:('a', 1, 12), 5:('r', 21, 10), 2:('u', 9, 8)}
>>>> t = [x for x in d.values()]
>>>> def third(mls):
> ...     return mls[2]
> ...
>>>> s = sorted(t, key=third)
>>>> pres = []
>>>> for x in s:
> ...     for k in d.keys():
> ...         if d[k] == x:
> ...             pres.append(k)
> ...             break
> ...
>>>> res = []
>>>> for x in pres:
> ...     res.append((x, d[x]))
> ...
>>>> res
> [(2, ('u', 9, 8)), (5, ('r', 21, 10)), (1, ('a', 1, 12))]
>>>>
>
> Can you provide me a much pythonic solution (with comments if possible,
> so I can actually learn something)?
>
> Thanks, Mattia
> --
> http://mail.python.org/mailman/listinfo/python-list
>
I won't engage in any arguments about pythonicity but it seems simpler
if you convert to a list of tuples right away.

d = {1:('a', 1, 12), 5:('r',21,10), 2:('u',9,8)}
l = [(x, d[x]) for x in d.keys()]
def third(q):
    return q[1][2]

s = sorted(l, key=third)
print s