Sort the values of a dict

[Chris Kaynor]

I'd write it as:
s = sorted(d.iteritems(), key=lambda i: i[1][2])

If using python 3, it should be d.items() instead of d.iteritems().

d.iteritems() is a generator yielding tuples of (key, value) from
the dictionary 'd'.
lambda i: i[1][2] is the same as:
def sort_(i):
    return i[1][2]
but in-line.

Chris


On Fri, Dec 18, 2009 at 2:34 PM, mattia <gervaz at gmail.com> wrote:

> Hi all, I have a dictionary that uses dates and a tuples ad key, value
> pairs. I need to sort the values of the dict and insert everything in a
> tuple. The additional problem is that I need to sort the values looking
> at the i-th element of the list. I'm not that good at python (v3.1), but
> this is my solution:
>
> >>> d = {1:('a', 1, 12), 5:('r', 21, 10), 2:('u', 9, 8)}
> >>> t = [x for x in d.values()]
> >>> def third(mls):
> ...     return mls[2]
> ...
> >>> s = sorted(t, key=third)
> >>> pres = []
> >>> for x in s:
> ...     for k in d.keys():
> ...         if d[k] == x:
> ...             pres.append(k)
> ...             break
> ...
> >>> res = []
> >>> for x in pres:
> ...     res.append((x, d[x]))
> ...
> >>> res
> [(2, ('u', 9, 8)), (5, ('r', 21, 10)), (1, ('a', 1, 12))]
> >>>
>
> Can you provide me a much pythonic solution (with comments if possible,
> so I can actually learn something)?
>
> Thanks, Mattia
> --
> http://mail.python.org/mailman/listinfo/python-list
>
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