best way to compare contents of 2 lists?
Hans DushanthaKumar
hans.dushanthakumar at hcn.com.au
Thu Apr 23 21:37:09 EDT 2009
'set' comes to mind, though I'm not sure if there are performance
inplications with large amopunts of data.
>>> a=[1, 2, 3]
>>> b=[2, 3, 1]
>>> set(a) == set(b)
True
Cheers,
Hans
-----Original Message-----
From: python-list-bounces+hans.dushanthakumar=hcn.com.au at python.org
[mailto:python-list-bounces+hans.dushanthakumar=hcn.com.au at python.org]
On Behalf Of Esmail
Sent: Friday, 24 April 2009 11:31 AM
To: python-list at python.org
Subject: best way to compare contents of 2 lists?
What is the best way to compare the *contents* of two different
lists regardless of their respective order? The lists will have
the same number of items, and be of the same type.
E.g. a trivial example (my lists will be larger),
a=[1, 2, 3]
b=[2, 3, 1]
should yield true if a==b
I suppose I could sort them and then compare them. I.e.,
sorted(a)==sorted(b)
I am wondering if there is a more efficient/preferred way to do so.
Thanks,
Esmail
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