Scott David Daniels wrote: > Assuming you really are going for "is" comparison, how about: > max(id(x) for x in mylist) == min(id(x) for x in mylist) > > It has the advantage that if [id(x) for x in mylist] = [2N, 1N, 3N], > you get the answer you desire. > Oops -- got me! -John