How to check all elements of a list are same or different

[Gaurav Moghe]

Thanks! That works!

On Wed, Apr 15, 2009 at 6:14 PM, Chris Rebert <clp2 at rebertia.com> wrote:

> > On Wed, Apr 15, 2009 at 5:49 PM, Chris Rebert <clp2 at rebertia.com> wrote:
> >>
> >> On Wed, Apr 15, 2009 at 2:36 PM, Gaurav Moghe <moghegau at msu.edu> wrote:
> >> > Hi,
> >> >
> >> > I am an amateur python user I wanted to know how do I know whether all
> >> > the
> >> > contents of a list are all same or all different? Now, I could
> certainly
> >> > write a loop with a counter. But is there a ready command for that?
> >> > Checked
> >> > a lot of docs and this mailing list, but didnt get anything
> worthwhile.
> >> > Would be glad to know.
> >>
> >> All same:
> >>
> >> list_1 == list_2
> >>
> >> All different:
> >>
> >> all(x != y for x, y in zip(list_1, list_2))
> >>
> On Wed, Apr 15, 2009 at 2:55 PM, Gaurav Moghe <moghegau at msu.edu> wrote:
> > Hi Chris,
> >
> > Thanks for the reply. But I am interested in analysing the contents of
> just
> > one list. For example,
> >
> > list1=[1,2,3,4,5,6]
> > So, the logical statement would probably be:
> > if list1==(contains all same values), print "Same"    ---->False
> > if list1==(contains all different values), print "Different"  ---->True
> >
> > I wanted to know here whether there is a command/function that can do
> > exactly this.  I hope I am more clearer than my last try!
>
> Ah, okay. Then you want:
>
> def all_same(lst):
>    return len(set(lst)) == 1
>
> def all_different(lst):
>    return len(set(lst)) == len(lst)
>
> Note that these require all the elements of the list to be hashable.
>
> Cheers,
> Chris
> --
> I have a blog:
> http://blog.rebertia.com
>
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