Enumerating ordered expat attributes with tuplets?

Manuel Ebert maebert at uos.de
Thu Sep 11 11:04:43 EDT 2008


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Hi Andy,

by the looks of it I'd say that the problem is that the second  
parameter you passed to start_element is not a dictionary at all (the  
clue is in the "AttributeError: 'LIST' object" ...).

 >>> d = ['tree', 'house']
 >>> start_element("Thing", d)
Thing :
AttributeError: 'list' object has no attribute 'items'
 >>> d = {'tree': 'hug', 'flower' : 'eat'}
 >>> start_element("Thing", d)
Thing :   flower="eat"  tree="hug"

Manuel

On Sep 11, 2008, at 4:21 PM, andy_westken at hotmail.com wrote:

> Hi
>
> I'm new to Python and trying to pick up good, idiomatic usage right
> from the offset.
>
> As I was familiar with Expat from C++ (directly and via expatpp) I'm
> trying to write a little script - using xml.parsers.expat - to search
> and replace XML attribute values.
>
> As I want the attributes to stay in order when the file is written out
> (so I can check my results with a diff tool) I've set the parser's
> ordered_attributes attribute. But this has stopped the for loop
> working with the tuplets.
>
> The relevant bit of code in my little test, using the default
> Dictionary for the attributes, is:
>
> def start_element(name, attrs):
>     print "%s : " % name,
>     for (a,b) in attrs.items():
>         print " %s=\"%s\"" % (a,b),
>
> But when I set ordered_attributes, first it doesn't like the items()
>
>     AttributeError: 'list' object has no attribute 'items'
>
> And then it doesn't like the tuple
>
>     ValueError: too many values to unpack
>
> Do I have keep track of where I am (name, value, name, value, ...)
>
> Or is there a way I can solve the problem with a tuple?
>
> Thanks, Andy
> --
> http://mail.python.org/mailman/listinfo/python-list
>

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