generate random digits with length of 5
Gary M. Josack
gary at byoteki.com
Sun Sep 28 16:11:20 EDT 2008
Chris Rebert wrote:
> On Sun, Sep 28, 2008 at 12:59 PM, sotirac <sotirac at gmail.com> wrote:
>
>> Wondering if there is a better way to generate string of numbers with
>> a length of 5 which also can have a 0 in the front of the number.
>>
>>
>> <pre>
>> random_number = random.sample([0,1,2,3,4,5,6,7,8,9], 5) # choose 5
>> elements
>> code = 'this is a string' + str(random_number[0]) +
>> str(random_number[1]) + str(random_number[2]) + str(random_number[3])
>> + str(random_number[4])
>>
>
> code = ''.join(str(digit) for digit in random_number)
>
> Regards,
> Chris
>
>
>> </pre>
>>
>> --
>> http://mail.python.org/mailman/listinfo/python-list
>>
>>
will random.randint(10000,99999) work for you?
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