generate random digits with length of 5

[sotirac]

On Sep 28, 5:22 pm, "Aaron \"Castironpi\" Brady"
<castiro... at gmail.com> wrote:
> On Sep 28, 4:08 pm, Michael Ströder <mich... at stroeder.com> wrote:
>
>
>
> > Gary M. Josack wrote:
> > > Aaron "Castironpi" Brady wrote:
> > >> On Sep 28, 2:59 pm, sotirac <soti... at gmail.com> wrote:
>
> > >>> Wondering if there is a better way to generate string of numbers with
> > >>> a length of 5 which also can have a 0 in the front of the number.
>
> > >>> <pre>
> > >>>  random_number = random.sample([0,1,2,3,4,5,6,7,8,9], 5) # choose 5
> > >>> elements
> > >>>  code = 'this is a string' + str(random_number[0]) +
> > >>> str(random_number[1]) + str(random_number[2]) + str(random_number[3])
> > >>> + str(random_number[4])
> > >>> </pre>
>
> > >> '%05i'%random.randint(0,99999)
> > >> --
> > >>http://mail.python.org/mailman/listinfo/python-list
>
> > > This produces numbers other than 5 digit numbers. making the start
> > > number 10000 should be fine.
>
> > Why do you think it's wrong?
>
> > >>> import random
> > >>> '%05i'%random.randint(0,99999)
> > '09449'
>
> > IMO it's exactly what was required.
>
> > Ciao, Michael.
>
> As you read, there isn't agreement on whether the OP wanted
> replacement.  His original code didn't; his spec seemed to.

My value of the result string can be '00000' to '99999'.