Clever way of sorting strings containing integers?

[Holger]

On 9 Okt., 10:57, Marc 'BlackJack' Rintsch <bj_... at gmx.net> wrote:
> On Thu, 09 Oct 2008 00:41:27 -0700, Holger wrote:
> > I tried to do this elegantly, but did not come up with a good solution
>
> > Sort strings like
> > foo1bar2
> > foo10bar10
> > foo2bar3
> > foo10bar2
>
> > So that they come out:
> > foo1bar2
> > foo2bar3
> > foo10bar2
> > foo10bar10
>
> > I.e. isolate integer parts and sort them according to integer value.
>
> import re
>
> def key_func(string):
>     result = re.split(r'(\d+)', string)
>     for i in xrange(1, len(result), 2):
>         result[i] = int(result[i])
>     return result
>
> def main():
>     lines = ['foo1bar2',
>              'foo10bar10',
>              'foo2bar3',
>              'foo10bar2',
>              'fo',
>              'bar1000',
>              '777']
>     lines.sort(key=key_func)
>     print '\n'.join(lines)

Perfect!
Thank you.