how to call this dll in python

[Mark Tolonen]

"Shark" <ysystudio at gmail.com> wrote in message 
news:eb620337-0a9e-4d50-ab66-cfeeaba18dc4 at v39g2000pro.googlegroups.com...
>I have a windows dll1.dll with a export function:
>
> int f1(char filename,char **buf,int *bufLen)
> {
> int len;
> //got the length of file anyway,such as 100
> len = 100;//len = getLen(filename);
> *buf = (char*)calloc(100);
> *bufLen = len;
> return 0;
> }
>
> then how can I call the f1 function with python.
> thanks for your response.

Here's a quick, tested example.  It's not pretty but demonstrates what you 
want:

===== begin C DLL code =======
#include <string.h>
#include <stdlib.h>
#include <stdio.h>

__declspec(dllexport)
int get(const char* filename,char **buf,int *bufLen)
{
 int i,len;
 printf("*buf before malloc=%p\n",*buf);
 len = strlen(filename);
 *buf = (char*)malloc(len);
 *bufLen = len;
 for(i=0;i<len-1;i++)
      (*buf)[i]='a';
 (*buf)[i]=0;
 printf("*buf after malloc=%p\n",*buf);
 return 5;
}

__declspec(dllexport)
void release(char* buf)
{
 printf("buf[0]=%d\n",buf[0]);
 printf("buf=%p\n",buf);
 free(buf);
}
===== end C DLL code =======

===== begin Python code =======
from ctypes import *
x = CDLL('x.dll')
x.get.argtypes=[c_char_p,POINTER(POINTER(c_byte)),POINTER(c_int)]
buf = POINTER(c_byte)()
length = c_int()
print x.get("hello.txt",byref(buf),byref(length))
print repr(string_at(buf,length))
buf[0]=55 # change first byte
x.release.argtypes=[POINTER(c_byte)]
x.release(buf)
===== end Python code =======

sample output:

*buf before malloc=00000000
*buf after malloc=00C92940
5
'aaaaaaaa\x00'
buf[0]=55
buf=00C92940

-Mark