Multiple equates

[Tim Chase]

> It doesn't matter as none of this is valid Python. In Python you have to
> write
> 
> array[x1] = False
> array[x2] = False

Uh...not so much...

  >>> a = [1,2,3,4,5]
  >>> x1, x2 = 1, 3
  >>> a[x1] = a[x2] = False
  >>> a
  [1, False, 3, False, 5]

Works for me.

To the OP, I think rather than cluttering my code, I'd just 
create a loop

   for i in [x1,x2,x3,x4,...x1024]:
     a[i] = False

 From Diez's disassembly of it (as an aside, nifty little intro 
to dis.dis()...thanks, Diez!), it looks like it boils down to "is 
DUP_TOP faster than LOAD_CONST" because the rest of the 
operations.  At this point, it's pretty nitty-gritty.

Unless the code is in an inner loop somewhere, the simple loop 
should be more than fast enough.  Without knowing the source of 
the [x1,...] index variables, it's hard to tell if there's a more 
optimal way to do this.

-tkc