Is the behavior expected?

[Alphones]

On 11月26日, 下午8时48分, "Diez B. Roggisch" <de... at nospam.web.de> wrote:
> Alphones wrote:
> > Hi all,
>
> > def getFunc(x):
> >     return lambda y : x + y
>
> > if __name__ == '__main__':
> >     todo = []
> >     proc = getFunc(1)
> >     todo.append(lambda: proc(1))
> >     proc = getFunc(2)
> >     todo.append(lambda: proc(1))
> >     proc = getFunc(3)
> >     todo.append(lambda: proc(1))
>
> >     todo.append(lambda: getFunc(1)(1))
> >     todo.append(lambda: getFunc(2)(1))
> >     todo.append(lambda: getFunc(3)(1))
>
> >     for task in todo:
> >         print task()
>
> > -----------
> > the program outputs:
> > 4
> > 4
> > 4
> > 2
> > 3
> > 4
> > in Python 2.6.
> > is that excpected?
>
> Yes. Creating a lambda will close over the current *names* in the scope,
> *not* their respective values. For that, you need to create a new scope -
> e.g. by bindig the value to a argument of the lambda:
>
> lambdas = []
> for i in xrange(10):
>     lambda i=i : i ** 2
>
> for l in lambdas:
>     l()
>
> Diez

thanks :D
now I know what's wrong with my program.
it is a little deferent from other script language.