do you fail at FizzBuzz? simple prog test

[Max Erickson]

Arnaud Delobelle <arnodel at googlemail.com> wrote:

> On May 12, 1:30 pm, John Machin <sjmac... at lexicon.net> wrote:
>> Duncan Booth wrote:
> [...]
>> > I think the variant I came up with is a bit clearer:
>>
>> > for i in range(1,101):
>> >    print '%s%s' % ('' if i%3 else 'Fizz', '' if i%5 else
>> > 'Buzz') or 
>  i
>>
>> More than a bit clearer, IMO. How about
>>      print ('' if i%3 else 'Fizz') + ('' if i%5 else 'Buzz') or
>> i (or perhaps
>>      print (('' if i%3 else 'Fizz') + ('' if i%5 else 'Buzz'))
>> or i to save looking up the precedence rules) ?
> 
> Stuff clarity!  How about
> 
> for i in xrange(1, 101):
>     print 'FizzBuzz'[4*(i%3>0):4+4*(i%5<1)] or i
> 
> --
> Arnaud
> 
> --
> http://mail.python.org/mailman/listinfo/python-list
> 
> 

With no loop:

i=1
exec"print'FizzBuzz'[4*(i%3>0):4+4*(i%5<1)]or i;i+=1;"*100


max