slicing lists

[Ivan Illarionov]

On Wed, 07 May 2008 21:13:27 -0400, Miles wrote:

> On Wed, May 7, 2008 at 7:46 PM, Ivan Illarionov
>  <ivan.illarionov at gmail.com> wrote:
>  > On Wed, 07 May 2008 23:29:27 +0000, Yves Dorfsman wrote:
>  >
>  >  > Is there a way to do:
>  >  > x = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
>  >  > x[0,2:6]
>  >  >
>  >  > That would return:
>  >  > [0, 3, 4, 5, 6]
>  >
>  >  IMHO this notation is confusing.
>  >
>  >  What's wrong with:
>  >  [0]+x[2:6]
> 
>  I think Yves meant to return [1, 3, 4, 5, 6], as in Perl's list
>  slicing:
> 
>  my @x = (1, 2, 3, 4, 5, 6, 7, 8, 9, 10); return @x[0, 2..6]; // returns
>  (1, 3, 4, 5, 6)

So it should be x[0] + x[2:6] or x[0].extend(x[2:6])