i want to add a timeout to my code

[Gabriel Genellina]

En Thu, 01 May 2008 17:06:20 -0300, maehhheeyy <maehhheeyy at gmail.com>  
escribió:
> On Apr 29, 3:29 pm, John Krukoff <jkruk... at ltgc.com> wrote:
>> On Tue, 2008-04-29 at 14:47 -0700, maehhheeyy wrote:
>> > On Apr 17, 4:24 pm, Miki <miki.teb... at gmail.com> wrote:
>> > > On Apr 17, 1:10 pm,maehhheeyy<maehhhe.. at gmail.com> wrote:
>>
>> > > > I want to add a timeout so that when I pull out my gps from my  
>> serial
>> > > > port, it would wait for a bit then loop and then see if it's  
>> there. I
>> > > > also want to add a print statement saying that there is no GPS  
>> device
>> > > > found. However when I run my code and unplug my serial port, my  
>> code
>> > > > will just hang until I plug it back in.
>> > > > This is my code right now:
>>
>> > > > def GetGPS():
>> > > >       data = []
>> > > >       #Open com1: 9600,8,N,1
>> > > >       fi = serial.Serial(0, timeout = 1)
>> > > >       print '[gps module] SERIAL PORT OPEN ON COM1:'
>>
>> > >http://docs.python.org/lib/node545.html
>>
>> > I tried the code onto my codes but what came out was that in the line
>> > signal.signal(signal.SIGSLRM, handler), an attributeError appeared
>> > reading that 'module' object has no attribute 'SIGALRM'
>> > --
>> Are you writing your program on windows, or some other platform which is
>> not unix?
>>
> Yeah I'm using Windows 2000.

signal doesn't work on Windows. The timeout parameter to Serial should  
suffice...

-- 
Gabriel Genellina