call f(a, *b) with f(*a, **b) ?

[inhahe]

"inhahe" <inhahe at gmail.com> wrote in message 
news:MKwZj.2749$772.668 at bignews2.bellsouth.net...

> if we assume the constraints are that:
> 1.he has list, l
> 2.he has a dictionary, d
> 3.he wants the function to print the values in the dictionary according to 
> a specific order of their keys as defined by the function, followed by the 
> values of the list

It's also possible (even likely) that he knows outside of the function what 
order he wants the values in, and only used an (incidentally) unordered dict 
called kwargs because he thought that's the only way to pass to those 
parameters.  in which case the function could be left untouched and the he 
would call it like this:

args = [1,2,3]
f(*args)
or
f(*[1,2,3])