Newbie: Keep TCP socket open

[Alan Wright]

Thanks for the feedback.

Using the socket in a list is great

However, as i imagined, I now get a limit of around 1500 conns before the 
system crashes out, also i have noticed, that the ports loop back to 1025 
when they hit 5000.

Any ideas on how to make the list/socket get to around 50K

TIA

Alan
<s0suk3 at gmail.com> wrote in message 
news:e8e610ae-dec8-4551-b769-28ce9254c2b1 at c58g2000hsc.googlegroups.com...
> On May 19, 10:25 am, "Alan Wright" <alan.wri... at volubill.com> wrote:
>> Hi Folks,
>> I am newbie to Python, but have successfully created a simple client and
>> server setup, I have one issue though.
>>
>> I am trying to test a box by sending many TCP conns (WHILE loop) but not
>> closing them with a FIN/RST. However, no matter what i do, i cannot get 
>> the
>> loop to stop sending FIN from the client.
>>
>> Any clues?
>>
>> Here is my current script
>>
>> #!/usr/bin/python
>>
>> import socket,sys
>> from numpy import *
>> num1=0
>>
>> while (num1<=10) :
>>
>>  s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
>>  s.settimeout(10.0)
>>  s.connect(("10.1.1.69", 50008)) # SMTP
>>  print s.recv(1024) + '\n',
>>  num1=num1+1
>>  #s.close()
>>
>> sys.exit(1)
>
> socket.socket instances do an implicit close() on the socket when the
> object is destructed (in this case, it's destructed when it is garbage-
> collected). What's happening is that on each iteration, the variable
> "s", which references the socket.socket instance, is assigned to a new
> socket.socket instance, therefore the instance of the previous
> iteration is no longer referenced by "s", and since it's no longer
> referenced by anything, the instance is garbage-collected,
> automatically imposing an implicit close() on that instance. A simple
> solution could be to create a list and append the socket.socket
> instance of each iteration to that list, that way the instances would
> remain referenced in the list and not be garbage-collected; though you
> might be able to find a more elegant solution.
>
> Sebastian