passing *args "recursively"

Guillermo guillermo.listas at googlemail.com
Mon May 12 12:19:00 EDT 2008


Hi,

This must be very basic, but how'd you pass the same *args several
levels deep?


def func2(*args)

    print args # ((1, 2, 3),)
    # i want this to output (1, 2, 3) as func1!
    # there must be some better way than args[0]?

def func1(*args):

    print args # (1, 2, 3)
    func2(args)

func1(1,2,3)

Thanks!

Guillermo



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