getattr(foo, 'foobar') not the same as foo.foobar?

[Bruno Desthuilliers]

Mel a écrit :
(snip)
> (What Diez said.)  From what I've seen, f.bar creates a bound method 
> object by taking the unbound method Foo.bar and binding its first 
> parameter with f. 

Nope. it's Foo.__dict__['bar'] (that is, the function bar defined in the 
namespace of class Foo) that creates a bound instancemethod object when 
looked up on a Foo instance - or an unbound instancemethod object when 
looked up on Foo. FWIW, types.UnboundMethodType and types.MethodType are 
both aliases to instancemethod type.