Is this doable

[Gabriel Genellina]

On 21 mar, 15:11, MRAB <goo... at mrabarnett.plus.com> wrote:
> On Mar 21, 11:48 am, fkallgren <fkallg... at gmail.com> wrote:> Hi.
>
> > I have a little problem. I have a script that is in the scheduler
> > (win32). But every now and then I update this script and I dont want
> > to go to every computer and update it. So now I want the program to 1)
> > check for new version of the script, 2) if there is a new version,
> > copy that verision from server to local drive, 3) shutdown the program
> > and start it up again as the new version.
>
> > The problem is that I can't run this script directly from server so it
> > have to run it locally.
>
> > Anyone having any bright ideas??
>
> import os
> import sys
> import shutil
>
> # Is there a newer version?
> my_path = sys.argv[0]
> update_path = os.path.join(os.path.dirname(my_path), "new_script.py")
>
> if os.path.getmtime(my_path) < os.path.getmtime(update_path):
>     # Update the script.
>     shutil.copy2(update_path, my_path)
>     # Re-start the script.
>     os.startfile(my_path)
>     sys.exit()
>
> # The rest of the script...

I do mostly the same, except that instead of os.startfile I use:

  args = [sys.executable]
  args.extend(sys.argv)
  os.spawnl(os.P_NOWAIT, sys.executable, *args)

to re-start the current script with the same arguments it was invoked
before.

--
Gabriel Genellina