Difference between 'function' and 'method'
Gabriel Genellina
gagsl-py2 at yahoo.com.ar
Thu Mar 6 06:35:07 EST 2008
En Wed, 05 Mar 2008 02:57:58 -0200, <castironpi at gmail.com> escribi�:
>> > > >> >> Can you overload -type-'s decision of what to 'bind'?...
>> whenever it
>> > > >> >> is it makes it.
>>
>> > > >> Use delegation instead of inheritance. This class is almost
>> > > >> indistinguishable from a true function (when used as a method):
>>
>> Notwithstanding. Now bar has a name.
> Now func has it.
>
> from functools import wraps
> class myfunction:
> __slots__ = ('func','name')
> #
> def __init__(self, func):
> @wraps( func )
> def f( *ar, **kws ):
> return func( self, *ar, **kws )
> object.__setattr__(self, 'func', f)
> object.__setattr__(self, 'name', None)
> #
> def __get__(self, instance, owner):
> print( "__get__ called for",instance )
> return self.func.__get__(instance, owner)
> #
> def __getattr__(self, name):
> return getattr(self.func, name)
> #
> def __setattr__(self, name, value):
> object.__setattr__(self.func, name, value)
>
> class mymeta( type ):
> def __init__( self, name, bases, namespace ):
> for k,v in namespace.items():
> if isinstance( v, myfunction ):
> v.name= k
>
> class P( metaclass= mymeta ):
> def foo(self, x): print( 'foo',x )
> #
> @myfunction
> def bar( fob,self, x): print( 'bar',fob,x )
>
> p= P()
> p.foo( 0 )
> p.bar( 1 )
> print( p.bar )
> print( p.bar.name )
Mmm, looks too complicated and I don't see any advantage over the original
code. Functions already know their (original) name: func_name. If `name`
was just an example, note that functions already have writeable attributes
too, and my code exposes them as well. This should work with that version
(untested):
p = P()
print p.bar.func_name # -> bar
p.bar.im_func.anotherattribute = 1
print p.bar.anotherattribute # -> 1
(the attribute must be set on the *function* itself if you want it to be
somewhat persistent; methods are usually volatile objects)
--
Gabriel Genellina
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