First post from a Python newbiw

[Steve Turner]

Christoph Zwerschke wrote: 

: Marc 'BlackJack' Rintsch schrieb:
:: On Sun, 02 Mar 2008 14:15:09 +0000, Steve Turner wrote:
:: 
::: Apart from doing something like
::: a=[0,0,0]
::: b=[0,0,0]
::: c=[0,0,0]
::: d=[a,b,c]
::: 
::: is there a better way of creating d??
:: 
:: a = [[0] * 3 for dummy in xrange(3)]
: 
: Why not simply [[0]*3]*3 ?

I've just tried that and it gives the same as my earlier b=[a,a,a]

-- 
Steve