Open a file with default handler app?

[Wubbulous at gmail.com]

On Mar 11, 9:24 pm, andrei.... at gmail.com wrote:
> Hi, I searched for this on google and in this group, but my awesome
> google-fu powers failed me. Is there a way to open any file using
> default program that'd open it? In other words, to do the same action
> as double-clicking in windows explorer? And secondly, is there a way
> to do the same thing for linux that'd work across all desktop
> environments and distributions, or at least in all major ones? What
> I'm trying to do here is to have records (or items) in my app where
> you could attach any kind of file and open it from there by clicking
> 'open'. Then it would go and do something like os.system("launch %s" %
> filename). So any way to do this except for keeping your own
> dictionary of file types and relevant apps? thx, -ak

Hey there,
I've had to do the same things for a program that I'm writing. The
following command should do the trick:

os.startfile("yourfilehere")

from the os module. Hope this helps!