While executing the class definition which object is referenced by the first argument of the class method, Y r Object attributes not allowed as default arguments

[castironpi at gmail.com]

On Mar 7, 11:49 am, Krishna <Krishna.0... at gmail.com> wrote:
> On Mar 6, 5:04 pm, "Gabriel Genellina" <gagsl-... at yahoo.com.ar> wrote:
>
>
>
>
>
> > En Thu, 06 Mar 2008 22:48:42 -0200, Krishna <Krishna.0... at gmail.com>
> > escribi�:
>
> > >>>> class Test(object):
> > > ...     def __init__(self):
> > > ...             self.a= 2
> > > ...     def func(self, k = self.a):
> > > ...             print k
> > > ...
> > > Traceback (most recent call last):
> > >   File "<stdin>", line 1, in ?
> > >   File "<stdin>", line 4, in Test
> > > NameError: name 'self' is not defined
>
> > > In the 'definition of the class', what would the first argument 'self'
> > > in the methods evaluate to; when we have an object defined, it is
> > > bound to the object reference, but what happens while the class
> > > definition is executed, which I believe happens when the module
> > > containing the class definition is imported
>
> > Function default arguments are evaluated when the function is defined
> > (when the class is defined, in this case) so "self" itself has not a
> > value. Try this instead:
>
> >      def func(self, k=None):
> >          if k is None:
> >              k = self.a
> >          print k
>
> > If None is an allowed argument, use a special marker instead:
>
> > _marker=object()
> > ...
>
> >      def func(self, k=_marker):
> >          if k is _marker:
> >              k = self.a
> >          ...
>
> > --
> > Gabriel Genellina
>
> Thanks for the reply. I am currently using the approach suggested by
> you. But, I am more interested in knowing about the first argument
> ('self'), what does it hold to allow the evaluation of the method,
> take the example you gave, 'self.a' as Rvalue inside the method, how
> and why is this allowed, when the same 'self.a' is not allowed as the
> default argument, considering the fact that I have already specified
> 'self' as first argument, only after whose evaluation, I believe would
> the next statement (k = self.a, in def func(self, k = self.a) ) gets
> evaluated
>
> Thanks,
> Krishna- Hide quoted text -
>
> - Show quoted text -

Is there enough information at that point in the statement to assign
to k as specified by this language?

No.

Does there exist a possible language in which there is?

Yes.