URLError

[Steven D'Aprano]

On Wed, 19 Mar 2008 14:45:39 -0700, Jim wrote:

> Program randomly aborts when looking up url. The program loop thru 
> 4000+ records looking
> up ID via internet and returns html code which is used in subsequent
> processing. The code
> for looking-up record is below followed by abort details. Can anyone
> help with catching the
> abort before program aborts or provide code to automatically start
> program? 


Yes. Wrap the offending code with a try...except loop, something similar 
to this.


try:
    contents = urllib2.urlopen(url).read()
except URLError, e:
    if e.errno == 10053:
        # "Software caused connection abort"
        response = raw_input(
            "Temporary failure, Skip/Halt/try Again?")
        response = response.lower().strip()
        if response in ('h', 'halt'):
            break
        elif response in ('a', 'again', 't', 'try', 'try again'):
            continue
        elif response in ('', 's', 'skip'):
            lines -= 1
            continue
        else:
            print "Unknown response, boo hiss to you!"
            raise


-- 
Steven