At 2008-06-18T10:32:48Z, cokofreedom at gmail.com writes: > # untested 2.5 > for keys in dict_one.items(): > if keys in dict_two: > if dict_one[keys] != dict_two[keys]: > # values are different > else: > # key is not present That fails if there is an item in dict_two that's not in dict_one. -- Kirk Strauser The Day Companies