Regular Expressions Quick Question

[Bruno Desthuilliers]

Rajanikanth Jammalamadaka a écrit :
(top-post corrected - Please, Rajanikanth, learn to trim&quote properly, 
and by all means avoid top-posting)
> 
> On Wed, Jul 9, 2008 at 12:13 AM, Lamonte Harris <pyth0nc0d3r at gmail.com> wrote:
>> Alright, basically I have a list of words in a file and I load each word
>> from each line into the array. 

<OP>
I assume you meant 'list' ?
</OP>

> Then basically the question is how do I
>> check if the input word matches multiple words in the list.
>>
>> Say someone input "test", how could I check if that word matches these list
>> of words:
>>
>> test
>> testing
>> tested
>>
>> Out of the list of
>>
>> Hello
>> blah
>> example
>> test
>> ested
>> tested
>> testing
>>
>> I want it to loop then check if the input word I used starts any of the
>> words in the list so if I typed 'tes'
>>
>> Then:
>>
>> test
>> testing
>> testing

<OP>
I assume you meant:
  test
  tested
  testing
</OP>

>> would be appended to a new array.

 > hi!
 >
 > Try this:
 >
 >>>> lis=['t','tes','test','testing']
 >>>> [elem for elem in lis if re.compile("^te").search(elem)]

Using a regexp for this is total overkill. But please at least use the 
proper regexp, and use re.compile correctly:

exp = re.compile(r'^tes')
found = [word for word in lis if exp.match(word)]

But you just don't need a regexp for this - str.startswith is your friend:

words = ['Hello', 'blah', 'example', 'test', 'ested', 'tested', 'testing']
found = [word for word in words if word.starswith('tes')]
assert found == ['test', 'tested', 'testing']

HTH