static variables in Python?

[Alan Franzoni]

kj was kind enough to say:

> In this case, foo is defined by assigning to it a closure that has
> an associated variable, $x, in its scope.
> 
> Is there an equivalent in Python?

There've been plenty of answers, and I'm not absolutely sure about what you
want... but closures are available in Python as well and you can use them,
and by combining them through the partial module you can get a sort of
closure factory:

from functools import partial

def getfunc(expensive_call, myfunc):
    val = expensive_call()

    f = partial(myfunc, val)

    return f



you can then do something like that:

>> f = getfunc(lambda: 1, lambda x,y:x*y)
>> f(2)
6





-- 
Alan Franzoni <alan.franzoni.xyz at gmail.com>
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