is possible to get order of keyword parameters ?

[Marc 'BlackJack' Rintsch]

On Fri, 25 Jan 2008 05:49:40 -0800, rndblnch wrote:

> def f(**kwargs):
>     <skipped>
>     return result
> 
> such as :
> f(x=12, y=24) == ['x', 'y']
> f(y=24, x=12) == ['y', 'x']
> 
> what i need is to get the order of the keyword parameters inside the
> function.
> any hints ?

Impossible.  Dictionaries are unordered.

Ciao,
	Marc 'BlackJack' Rintsch