removeall() in list

[castironpi at gmail.com]

On Jan 11, 5:43 pm, castiro... at gmail.com wrote:
> On Jan 11, 5:26 pm, Paul Rubin <http://phr...@NOSPAM.invalid> wrote:
>
> > castiro... at gmail.com writes:
> > > This function just wants X out of the list.  It doesn't matter if this
> > > happens before, during, or after something else; so long as it happens.
>
> > 2. Associate a lock with the list.  Anything wanting to access the
> > list should acquire the lock, do its stuff, then release the lock.
> > This gets confusing after a while.
>
> To keep it generic, how about:
>
> listA.op( insert, x )
> listA.op( remove, x )

However, in reality, your rock and hard place are:
listA.op( listA.insert, x )
listA.op( listA.remove, x )

or

listA.op( 'insert', x )
listA.op( 'remove', x )