itertools.groupby

[Tobiah]

Paul Rubin wrote:
> Tobiah <toby at tobiah.org> writes:
>> I tried doing this with a simple example, but noticed
>> that [].sort(func) passes two arguments to func, whereas
>> the function expected by groupby() uses only one argument.
> 
> Use: [].sort(key=func)

Oh cool.  Thanks.

Only in 2.4+ it seems.


>>> a = [1,2,3,4,5]
>>> def sorter(thing):
...     return thing % 2 == 0
...
>>> a.sort(key = sorter)
>>> print a
[1, 3, 5, 2, 4]
>>>


Nifty

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