How to solve "TypeError: list indices must be integers".

[顏灝]

On 1月22日, 上午1時56分, Dennis Lee Bieber <wlfr... at ix.netcom.com> wrote:
> On Mon, 21 Jan 2008 08:15:02 -0800 (PST), "ÃCø¯" <princi... at gmail.com>
> declaimed the following in comp.lang.python:
>
> > I was assigned dialog.colorDialog(self) return value to a result
> > object, but I suspect that result.color is the attribute of the result
> > object that can assign to a string variable.
>
>         Showing the actual code would help...
>
> > There is a error prompt from python console "TypeError: list indices
> > must be integers".
> > Have any suggestion to solve this problem?
>
>         Make sure you only have an integer when subscripting into a list?
>
> > When I print  result.color, it is print out something like (255,0,0).
>
>         Looks like a tuple -- probably
>                 (red-level, green-level, blue-level)
> where *-level is in the range 0..255 (x00..xFF); your example would be
> (full red, no green, no blue)
>
> > How to covert result.color into a string?  How to convert a string to
> > result.color type?
>
>         What type of string?
>                 "0x%2.2X%2.2X%2.2X" % (r, g, b)
> will produce a hex string of the form
>                 0xFF0000
> given your sample RGB
>
>         If you want to get "Red", you'll need a look-up table and probably
> some least-distance error function for items that don't directly match.
>
> (255, 0, 0)             Red
> (255, 255, 0)   Yellow
> (255, 0, 255)   Magenta
> (0, 255, 0)             Green
> (0, 255, 255)   Cyan
> (0, 0, 255)             Blue
> (0, 0, 0)               Black
> (255, 255, 255) White
>
>         But where would you put:        (127, 127, 63)          [A half-black Yellow
> with 1/4 blue added].. Is it closer to Yellow, or to Black: 255-127 =>
> 128, but 127 - 0 => 127... Shorter simplistic distance means map this to
> (0, 0, 0)... But (128, 128, 64) simplistic shorter distance would map to
> Yellow
>
> --
>         Wulfraed        Dennis Lee Bieber               KD6MOG
>         wlfr... at ix.netcom.com                wulfr... at bestiaria.com
>                 HTTP://wlfraed.home.netcom.com/
>         (Bestiaria Support Staff:               web-a... at bestiaria.com)
>                 HTTP://www.bestiaria.com/

Many thanks, Dennis Lee Bieber for your fast reply!
Regards,
Andreas