searching an XML doc
grflanagan
grflanagan at yahoo.co.uk
Wed Jan 16 05:21:28 EST 2008
On Jan 15, 9:33 pm, Gowri <gowr... at gmail.com> wrote:
> Hello,
>
> I've been reading about ElementTreee and ElementPath so I could use
> them to find the right elements in the DOM. Unfortunately neither of
> these seem to offer XPath like capabilities where I can find elements
> based on tag, attribute values etc. Are there any libraries which can
> give me XPath like functionality?
>
> Thanks in advance
Create your query like:
ns0 = '{http://a.b.com/phedex}'
query = '%srequest/%sstatus' % (ns0, ns0)
Also, although imperfect, some people have found this useful:
http://gflanagan.net/site/python/utils/elementfilter/elementfilter.py.txt
[CODE]
test = '''<phedexData xmlns="http://a.b.com/phedex"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://a.b.com/phedex requests.xsd">
<!-- Low priority replication request -->
<request id="1234" last_update="1060199000.0">
<status>
<approved>T1_RAL_MSS</approved>
<approved>T2_London_ICHEP</approved>
<disapproved>T2_Southgrid_Bristol</
disapproved>
<pending/>
<move_pending/>
</status>
<subscription open="1" priority="0" type="replicate">
<items>
<dataset>/PrimaryDS1/ProcessedDS1/
Tier</dataset>
<block>/PrimaryDS2/
ProcessedDS2/Tier/block</block>
</items>
</subscription>
</request>
</phedexData>
'''
from xml.etree import ElementTree as ET
root = ET.fromstring(test)
ns0 = '{http://a.b.com/phedex}'
from rattlebag.elementfilter import findall, data
#http://gflanagan.net/site/python/utils/elementfilter/
elementfilter.py.txt
query0 = '%(ns)srequest/%(ns)sstatus' % {'ns': ns0}
query1 = '%(ns)srequest/%(ns)ssubscription[@type=="replicate"]/%
(ns)sitems' % {'ns': ns0}
query2 = '%(ns)srequest[@id==1234]/%(ns)sstatus/%(ns)sapproved' %
{'ns': ns0}
print 'With ElementPath: '
print root.findall(query0)
print
print 'With ElementFilter:'
for query in [query0, query1, query2]:
print
print '+'*50
print 'query: ', query
print
for item in findall(root, query):
print 'item: ', item
print 'xml:'
ET.dump(item)
print '-'*50
print
print 'approved: ', data(root, query2)
[/CODE]
[OUTPUT]
With ElementPath:
[<Element {http://a.b.com/phedex}status at b95ad0>]
With ElementFilter:
++++++++++++++++++++++++++++++++++++++++++++++++++
query: {http://a.b.com/phedex}request/{http://a.b.com/phedex}status
item: <Element {http://a.b.com/phedex}status at b95ad0>
xml:
<ns0:status xmlns:ns0="http://a.b.com/phedex">
<ns0:approved>T1_RAL_MSS</ns0:approved>
<ns0:approved>T2_London_ICHEP</ns0:approved>
<ns0:disapproved>T2_Southgrid_Bristol</
ns0:disapproved>
<ns0:pending />
<ns0:move_pending />
</ns0:status>
++++++++++++++++++++++++++++++++++++++++++++++++++
query: {http://a.b.com/phedex}request/{http://a.b.com/
phedex}subscription[@type
=="replicate"]/{http://a.b.com/phedex}items
item: <Element {http://a.b.com/phedex}items at b95eb8>
xml:
<ns0:items xmlns:ns0="http://a.b.com/phedex">
<ns0:dataset>/PrimaryDS1/ProcessedDS1/
Tier</ns0:
dataset>
<ns0:block>/PrimaryDS2/
ProcessedDS2/Tier
/block</ns0:block>
</ns0:items>
++++++++++++++++++++++++++++++++++++++++++++++++++
query: {http://a.b.com/phedex}request[@id==1234]/{http://a.b.com/
phedex}status/
{http://a.b.com/phedex}approved
item: <Element {http://a.b.com/phedex}approved at b95cd8>
xml:
<ns0:approved xmlns:ns0="http://a.b.com/phedex">T1_RAL_MSS</
ns0:approved>
item: <Element {http://a.b.com/phedex}approved at b95cb0>
xml:
<ns0:approved xmlns:ns0="http://a.b.com/phedex">T2_London_ICHEP</
ns0:approved>
--------------------------------------------------
approved: ['T1_RAL_MSS', 'T2_London_ICHEP']
INFO End logging.
[/OUTPUT]
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