network programming: how does s.accept() work?

[Gabriel Genellina]

En Mon, 25 Feb 2008 20:03:02 -0200, 7stud <bbxx789_05ss at yahoo.com>  
escribió:
> On Feb 25, 10:56 am, Thomas Bellman <bell... at lysator.liu.se> wrote:
>> 7stud <bbxx789_0... at yahoo.com> wrote:

> In either case, there are still some things about the output that
> don't make sense to me.  Why does the server initially report that its
> ip address is 0.0.0.0:
>
> original socket: ('0.0.0.0', 5053)

Because you called "bind" with None (or '' ?) as its first argument; that  
means: "listen on any available interface"

> I would expect the reported ip address to be '127.0.0.1'.  Also, since
> a socket is uniquely identified by an ip address and port number, then
> the ('0.0.0.0', 5053) socket is not the same as this socket:
>
> new socket, self: ('127.0.0.1', 5053)

You got this *after* a connection was made, coming from your own PC.   
127.0.0.1 is your "local" IP; the name "localhost" should resolve to that  
number. If you have a LAN, try running the client on another PC. Or  
connect to Internet and run the "netstat" command to see the connected  
pairs.

-- 
Gabriel Genellina