regex question

[Wanja Chresta]

Hey Mathieu

Due to word wrap I'm not sure what you want to do. What result do you
expect? I get:
>>> print m.groups()
('0021', 'xx0A', 'Siemens: Thorax/Multix FD Lab Settings Auto Window
Width      ', ' ', 'SL', '1')
But only when I insert a space in the 3rd char group (I'm not sure if
your original pattern has a space there or not). So the third group is:
([A-Za-z0-9./:_ -]+). If I do not insert the space, the pattern does not
match the line.

I also cant see how the format of your line is. If it is like this:
line = "...Siemens: Thorax/Multix FD Lab Settings  Auto Window Width..."
where "Auto Window Width" should be the 4th group, you have to mark the
+ in the 3rd group as non-greedy (it's done with a "?"):
http://docs.python.org/lib/re-syntax.html
([A-Za-z0-9./:_ -]+?)
With that I get:
>>> patt.match(line).groups()
('0021', 'xx0A', 'Siemens: Thorax/Multix FD Lab Settings', 'Auto Window
Width         ', 'SL', '1')
Which probably is what you want. You can also add the non-greedy marker
in the fourth group, to get rid of the tailing spaces.

HTH
Wanja


mathieu wrote:
> I clearly mark that the separator in between group 3 and group 4
> should contain at least 2 white space, but group 3 is actually reading
> 3 +4