re question

Hyuga hyugaricdeau at gmail.com
Fri Feb 8 09:34:10 EST 2008


On Feb 7, 1:47 pm, Amit Gupta <emaila... at gmail.com> wrote:
> On Feb 7, 10:38 am, Amit Gupta <emaila... at gmail.com> wrote:
>
>
>
> > Python'ites
>
> > I searched around "google" to find the answer to this question, but I
> > can't:
>
> > I have a named regexp : x = re.compile("(?P<me>[a-z]+)")
>
> > What I want is an iterator, that can return me both the "groupname"
> > and the matched string,  e.g:
>
> > m = x.search("aa")
>
> > Somehow, I want to get
> > {"me" : "aa"}, either as dictionary or some iterable form.
>
> > All I found is, I need to know the "groupname" to get the
> > corresponding match. Any help is appreciated.
>
> > A
>
> Got It. re.search() has a function groupdict(), doing precisely that.

Just to be pedantic so that no one else who might read this does not
get confused, re.search() does not "[have] a function groupdict()".
re.search(), like many function in the re module returns a match
object.  Match objects have a groupdict() method.

Hyuga



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