newbie question: if var1 == var2:
MRAB
google at mrabarnett.plus.com
Thu Dec 11 19:39:24 EST 2008
Jason Scheirer wrote:
> On Dec 11, 3:49 pm, John Machin <sjmac... at lexicon.net> wrote:
>> On Dec 12, 10:31 am, "Rhodri James" <rho... at wildebst.demon.co.uk>
>> wrote:
>>
>>
>>
>>> On Thu, 11 Dec 2008 19:49:23 -0000, Steve Holden <st... at holdenweb.com>
>>> wrote:
>>>> Kirk Strauser wrote:
>>>>> At 2008-11-29T04:02:11Z, Mel <mwil... at the-wire.com> writes:
>>>>>> You could try
>>>>>> for item in fname:
>>>>>> item = item.strip()
>>>>> This is one case where I really miss Perl's "chomp" function. It
>>>>> removes a
>>>>> trailing newline and nothing else, so you don't have to worry about
>>>>> losing
>>>>> leading or trailing spaces if those are important to you.
>>>> ... and it's so hard to write
>>>> item = item[:-1]
>>> Tsk. That would be "chop". "chomp" would be
>>> if item[-1] == '\n':
>>> item = item[:-1]
>> Better:
>> if item and item[-1] == '\n':
>> return item[:-1]
>> return item
>
> Best:
>
> return item \
> if not (item and item.endswith('\n')) \
> else item[:-1]
>
> Though really you should be using item.rstrip()
>
Why not just:
item[:-1] if item.endswith('\n') else item
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