var or inout parm?

[sturlamolden]

On Dec 12, 1:56 pm, sturlamolden <sturlamol... at yahoo.no> wrote:

> That is because integers are immutable. When x += 1 is done on an int,
> there will be a rebinding. But try the same on say, a numpy array, and
> the result will be different:


And a consequence of this is, if you have a function like

def foobar(x):
   x += 1

then the parameter x will be modified given that x have mutable type.

However, if we have a function like

def foobar(x):
   x = x + 1

then x will not be modified, mutable or not.

(Well, you could abuse operator overlaoding to make unexpected side
effects in the latter case. But except for such insanity it will not
have side-effects.)