best way to do this

[TP]

Hi everybody,

>>> c=[(5,3), (6,8)]

>From c, I want to obtain a list with 5,3,6, and 8, in any order.
I do this:

>>> [i for (i,j) in c] + [ j for (i,j) in c]
[5, 6, 3, 8]

Is there a quicker way to do this?

Thanks

Julien
-- 
python -c "print ''.join([chr(154 - ord(c)) for c in '*9(9&(18%.9&1+,\'Z
(55l4('])"

"When a distinguished but elderly scientist states that something is
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