Problem with list.insert

[SUBHABRATA]

Some people in the room told I am kidding, but I learnt Python from
Python docs which gives examples like these,
But I write explicit comments,
an excerpt from python docs:
# Measure some strings:
... a = ['cat', 'window', 'defenestrate']
>>> for x in a:
...     print x, len(x)
...
cat 3
window 6
defenestrate 12
But well, if you are suggesting improvement I'll surely listen.

The outputs are given in Hindi, it is a dictionary look up program,
the matching words are in Hindi, you may leave aside them.
How to debug the result string is to see the words which are in
English as the group page does not take italics so I am putting one
asterisk* after it
NO PROBLEM:
INPUT:
he has come
OUTPUT IS
उओह/ उन्होने रहेसाक्ता २.यात्राकरना
PROBLEM:
INPUT:
(i) Lincoln* has come
OUTPUT IS:
रहेसाक्ता २.यात्राकरना lincoln*
lincoln lincoln* रहेसाक्ता २.यात्राकरना lincoln
lincoln lincoln* lincoln* रहेसाक्ता २.यात्राकरना lincoln
….and increasing the number and seems a never ending process.
MY EXPEPECTED STRING IS:
lincoln रहेसाक्ता २.यात्राकरना lincoln^
The latter places marked^ I am editing don't worry for that,
though MY FINAL EXPECTED STRING IS:
lincoln रहेसाक्ता २.यात्राकरना
Best Regards,
Subhabrata.



Marc 'BlackJack' Rintsch wrote:
> On Thu, 28 Aug 2008 09:13:00 -0700, SUBHABRATA wrote:
>
> > import re
> > def wordchecker1(n):
> >     # INPUTTING STRING
> >     a1=raw_input("PRINT ONE ENGLISH SENTENCE FOR DICTIONARY CHECK:")
> >     #CONVERTING TO LOWER CASE
> >     a2=a1.lower()
> >     #CONVERTING INTO LIST
> >     a3=a2.split()
> >     #DICTIONARY
> >     a4=open("/python25/Changedict3.txt","r") a5=a4.read()
> >     a6=a5.split()
> >     found=[]
> >     not_found=[]
> >    #SEARCHING DICTIONARY
> >     for x in a3:
> >         a7="\n"
> >         a8=a7+x
> >         if a8 in a5:
> >             a9=a5.index(a8)
> >             a10=a5[a9:]
> >             a11=re.search("\xe0.*?\n",a10)
> >             a12=a11.group()
> >             a13=a12[:-1]
> >             found.append(a13)
> >         elif a8 not in a5:
> >             a14=x
> >             not_found.append(a14)
> >         else:
> >             print "Error"
> >     found.extend(not_found)
> >     # THE OUTPUT
> >     print "OUTPUT STRING IS"
> >     a15=(' '.join(found))
> >     #THE OUTPUT STRING
> >     print a15
> >     # SPLITTING OUTPUT STRING IN WORDS
> >     a16=a15.split()
> >     #TAKING OUT THE WORD FROM OUTPUT STRING for word in a16:
> >         #MATCHING WITH GIVEN STRING
> >         a17=a2.find(word)
> >         if a17>-1:
> >             print "The word is found in the Source String"
> >             a18=a3.index(word)
> >             a19=a3[a18]
> >             print a19
> >             #INSERTING IN THE LIST OF TARGET STRING
> >             a20=a16.insert(a18,a19)
> >             print a16
> >             a21=(" ".join(a16))
> >             print a21
>
> a1, a2, a2, …, a20?  You must be kidding.  Please stop numbering names
> and use *meaningful* names instead!
>
> Could you describe them problem better, with sample inputs and expected
> outputs.  There must be a better way that that unreadable mess above.
>
> Ciao,
> 	Marc 'BlackJack' Rintsch